(6-x)^(x^2+7x+12)=1

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Solution for (6-x)^(x^2+7x+12)=1 equation: 



(6-x)^(x^2+7x+12)=1

We move all terms to the left:

(6-x)^(x^2+7x+12)-(1)=0

We add all the numbers together, and all the variables

(-1x+6)^(x^2+7x+12)-1=0

We move all terms containing x to the left, all other terms to the right

(-1x+6)^(x^2+7x+12)=1

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